I was wondering if anyone is good at unit conversions?

A recent survey found that 28% of the people who visit public pools urinate once while in the pool. The American average for the total urination is 1.8n liters per day, the event happens 3.6 times per day. The average urea concentration in urine is 7.5 mg/ml. let's say a community has a urine-free pool on the first day of the summer. The pool measures 25 meters long by 12 meters wide and has an average depth of 6 feet. at the end of the first day, a chemical analysis shows the urine concentration in the pool is 2 mg/L. Given this information how many people visited the pool on the first day?

I was wondering if anyone is good at unit conversions?
lets see.... urinate once in the pool... that is 1.8 liters divided by 3.6 times, or .5 liters each time. that is 500 ml... with 7.5mg urea per ml, that gives a total of 3750mg urea per urination... now the volume of the pool is 25m by 12m by 1.83m or a volume of 548,64 cubic meters. each cubic meter s 1000 liters, so we have 548640 liters in the pool. 2mg/l gives a total urea amount of 1097280 mg. divide this by the 3750 mg urea per urination and you get 292.6 urinations. Since only 28% of the visitors urinate, that makes the total number of visitors 1045

loops beats